Rhind Mathematical
Papyrus (4 of 8) / © 1979-2001 by Franz Gnaedinger, Zurich, fg(a)seshat.ch,
fgn(a)bluemail.ch / www.seshat.ch
Rhind 1 / Rhind 2 / Rhind 3 / Rhind 4 / Rhind 5 / Rhind 6 / Rhind 7 / Rhind 8
RMP 21, 22 and 23 - Re had many
names
By rolling a finely carved and polished stone disk on a carefully
prepared ground one may find that the ratio circumference to diameter is less than 4, a little more
than 3, less than 3 '6, and even a little less than 3 '7. These empirical
values or boundaries can be used for generating many more approximate values
for the number of the circle, which I call re, for the hieroglyph of the
supreme sun god Re was a small circle, and while he had many names, no one knew
his true one ...
You can easily see what I do:
4
(plus 3) 7 10
13 16 19
22 25 28
1
(plus 1) 2 3
4 5 6
7 8 9
If the diameter of a circle measures 7 palms or 1 royal cubit, the
circumference measures practically 22 palms or 3 cubits 1 palm.
6
(plus 19) 25 44 63
2
(plus 6) 8
14 20
Solve RMP 37 using the value '20 of 63 = 3 '10 '20.
9
(plus 19) 28 47
66 ... 256
3
(plus 6) 9
15 21 ...
81
A famous formula of the Rhind Mathematical Papyrus says that a
square with a side length of 8 royal cubits and a circle with a diameter of 9
royal cubits have roughly the same area. This formula is based on a value of
256/81 for pi.
3
(plus 22) 25 47
69 91 113
135 157 179
201 223 245
1
(plus 7) 8
15 22 29
36 43 50
57 64 71
78
267
289 311 333
355 377 399
421 443 465
487 509 531
85
92 99 106
113 120 127
134 141 148
155 162 169
If the side of a square measures 10 royal cubits or 70 palms, the
diagonal measures practically 99 palms, and the circumference of the circle
around the square measures practically 311 palms. - If you wish to know the
circumference of a circle, multiply the diameter by one of the following
series:
'99 of 311 = 3 '9 '33 '120 x 377 = 3 '8 '60 = 3 '10 '24
Yet another sequence:
6
(plus 22) 28 50
72 ... 424
... 600
2
(plus 7) 9
16 23 ...
135 ... 191
191/600 = '600 x 191 = '4 '30 '40 '100
If you know the circumference of a cylinder and wish to know its
diameter, multiply the circumference by '4 '30 '40 '100.
21
(plus 22) 43 65
... 2463
7
(plus 7) 14
21 ... 784 = 28x28
286 (+311)…
132 (+333)… 333 (+355)… 201 (+377)… 2463
91 (+ 99)…
42 (+106)… 106 (+113)… 84 (+120)…
784 = 28x28
If the radius of a circle measures 1 royal cubit or 28 fingers,
the area of the circle measures practically 2463 square fingers.
Now for RMP 21-23:
"3 '15 plus '5 '15
equals 1
"3 '30 plus '5 '10
equals 1
'4 '8 '10 '30 '45 plus
'9 '40 equals "3
I multiply the first equation by a factor of 135, the second one by
a factor of 50, and the third one by a factor of 360:
99 + 36 = 135 35 + 15 = 50 161 + 49 = 240
Consider these numbers as diameters of nine circles. How long are
their circumferences? Consulting the above number sequences you will derive the
following solutions and values of re:
c
47 22x5 113
22x7 157 311
424 600 377x2
d
15 7x5 36
7x7 50 99
135 191 120x2
These values can easily be given as unit fraction series:
'15 of 47
= 3 '10 '30 '7 of 22 = 3
'7
'36 of 113
= 3 '9 '36 '50 of 157 = 3
'10 '25
'99 of 311
= 3 '9 '33 '135 of 424 = 3
'15 '27 '135
'120 of 377
equals 3 '10 '24 or 3
'8 '60
'600 of 191
equals '4 '30 '40 '100
RMP 36 - a pair of granaries
3 '3 '5 times '4 '53 '106
'212 equals 1
Imagine a square whose diagonal measures 2 royal cubits. Its area
measures 2 square cubits.
Imagine a circle whose diagonal measures 3 royal cubits. Using the
value '135 of 424 for re, the area of the circle measures 7 '15 square cubits.
Build a granary on the square (inner diagonal 2 royal cubits).
Build a granary on the circle (inner diameter 3 royal cubits).
Fill the round granary to a height of 1 royal cubit. You will need
53 quadruple-hekat or 212 hekat of barley. Fill 212 hekat of grain in the
square granary. The barley will reach a height of 3 '3 '5 royal cubits.
Fill the square granary to a height of 1 royal cubit. You will
need 2 cubic cubits or 3 khar or 15 quadruple-hekat or 60 hekat of barley. Fill
60 hekat of barley in the round granary. It will reach a height of '4 '53 '106
'212 royal cubits.
RMP 31 - a granary on a ring
33 divided by
1 "3 '2 '7 equals 14 '4 '56 '194 '388 '679 '776
Imagine a regular hexagon whose side measures 66 fingers. Inscribe
and circumscribe a circle. The two circles form a ring. The radius of the outer
circle measures 66 fingers. How long is the radius of the inscribed circle in
palms?
1
1 3
2
4 6
1
2 3
3 5
9
3 5
9
8 14
24
4 7
12
11 19
33
30 52
90
15
26 45
41 71
123
112 194
336
56 97
168
The side of the hexagon measures 66 fingers. Multiply 66 fingers by
168/97 and you obtain the diameter of the inscribed circle in fingers. Multiply
33 fingers by 168/97 and you obtain the radius in fingers. Divide 33 fingers by
97/42 = 1 "3 '2 '7 and you obtain the radius of the inscribed circle in
palms:
33 fingers divided by
1 "3 '2 '7 equal 14 '4 '56 '97 '194 '388 '679 '776 palms
The area of the ring is given by the difference
area circumscribed
circle minus area inscribed circle
The area of the circumscribed circle is found as follows:
radius x radius x re
66 fingers x 66 fingers x
'99 x 311 = 13,684 square fingers
Now for the area of the inscribed circle. It measures
14 '4 '56 '194 '388 '679
'776 palms times 14 '4 '56 '194 '388 '679 '776 palms times
re
Is anyone prepared to carry out that multiplication ???
Ahmes would smile and offer a much simpler solution based on a
fine theorem:
Imagine a regular polygon of 3, 4, 5, 6, 7 ... equal sides. The
circumscribed circle and the inscribed circle form a ring. Draw a circle around
a side of the polygon. Its area equals the area of the ring.
The side of the regular hexagon measures 66 fingers, the radius of
the circle around a side measures 33 fingers, and the area of the ring measures
33 fingers x 33 fingers x
'99 x 311 = 3,421 square fingers
The area of the outer circle measures 13,684 square fingers, the
area of the ring measures 3,421 square fingers, and the area of the inner
circle measures 13,684 - 3,421 = 10,263 square fingers. Comparing these areas
reveals the following proportions:
area inner circle / area
ring / area outer circle = 3 / 1 / 4
Build a granary on the ring. If the height measures 5 '2 royal
cubits or 154 fingers, the volume of the wall measures practically 24 cubic
cubits, and the capacity 72 cubic cubits or 108 khar or 540 quadruple-hekat or
2160 hekat.
RMP 7 to 20 - spheres holding
rectangles
RMP 7
'4 '28 times 1 '2 '4 equals '2
Imagine a rectangle measuring '4 '28 by 1 '2 '4 royal cubits or 8
by 49 fingers. Its area measures half a square cubit. Transform this area into
a square, Its diagonal measures 1 royal cubit or 7 palms or 28 fingers. Draw a
circle around the square. How long is its circumference?
1 royal cubit
x '7 x 22 equals 3 '7 royal cubits
7 palms
x '7 x 22 equal 22 palms
28
fingers x '7 x 22 equal
88 fingers
The circumference measures 3 '7 royal cubits or 22 palms or 88
fingers (mistake less than one millimeter).
Partition the length of the rectangle 8 by 49 fingers according to
the number 1 '2 '4. Thus you obtain three rectangles measuring
'4 '28 by 1
royal cubit or 8 by 28 fingers
'4 '28 by '2 royal cubit or 8
by 14 fingers
'4 '28 by '4 royal cubit or 8
by 7 fingers
Imagine a sphere holding the rectangle 8 by 28 fingers and calculate
the surface of the sphere using the formula: area circle = diameter x diameter
x re. Choose a handy value of re from the number sequence
3
(plus 22) 25 47
69 91 113
... 311 333
355 377
1
(plus 7) 8
15 22 29
36 ... 99 106 113
120
The diameter squared is found as follows:
8x8 plus 28x28 = 64
plus 784 = 848
= 8 x 106
Using the value '106 of 333 for re we obtain
8 x 106 x '106 x 333 =
2,664 square fingers
The surface of the sphere around the rectangle 8 by 28 fingers
measures 2,664 square fingers (mistake 25 square millimeters). Imagine a sphere
holding the rectangle 8 by 7 fingers and calculate its surface in the same way:
8x8 plus 7x7 equals 113 113 x '113 x 355 equals 355
The surface of the sphere around the rectangle 8 by 7 fingers
measures 355 square fingers (mistake '94 square millimeter).
Imagine a sphere holding the long rectangle 8 by 49 fingers and
calculate the surface again, this time using the values '99 of 311 = 3 '9 '33
and '120 of 377 = 3 '8 '60. Round all the numbers:
8x8 plus 49x49 equals
2465
2465 x 3 '9 '33 --
7395 274 75
= 7744 square fingers
2465 x 3 '8 '60 --
7395 308 41
= 7744 square fingers
The surface of the sphere holding the rectangle 8 by 49 fingers
measures practically 7744 square fingers (mistake 9 square mm). Thus we found a
new value for re: '2465 of 7744
289
(plus 355) 649 999 ... 2419 ... 5969 ... 7389 7744
92
(plus 113) 205 318 ...
770 ... 1900 ... 2352 2465
Transform the area 7744 square fingers into a square:
7744 square fingers = 88 fingers by 88
fingers
The side of the square measures 88 fingers (mistake '362 mm). The
sphere around the rectangles 8 by 49 fingers holds another rectangle that
measures 23 by 44 fingers. Diameter squared:
8x8 plus 49x49 =
23x23 plus 44x44 = 2465 square fingers
The square 44 by 44 fingers and a circle around the rectangle 23
by 44 fingers have practically the same area:
44x44 = 23x23 plus 44x44 x '2465 x 7744 =
1936 square fingers
If you wish to transform a square into a circle of the same area
you may shorten the square from 44 to 23 equal parts and draw a circle around the resulting
rectangle. - A fairly good approximation is obtained by simply bisecting the
square. This solution is based on the value '81 of 256 for re.
RMP 8
'4 times 1 "3 '3 equals '2
A rectangle measures 7 by 56 fingers. The imaginary circle around
this rectangle circumscribes another rectangle that measures 28 by 49 fingers
or 1 by 1 '2 '4 royal cubits.
.
7x7 plus 56x56 = 28x28 plus 49x49 (diameter squared)
The periphery of the rectangle 28 by 49 fingers measures 154
fingers. Transform the periphery into the circumference of a circle. Use the
value '7 x 22 for re. You will obtain 49 fingers or 1 '2 '4 royal cubits.
154
f x '22 x 7 = 49 fingers or 1 '2 '4 royal cubits
RMP 9 '2 '14 times 1 '2 '4 equals 1
A rectangle measures 16 by 49 fingers. Imagine a sphere holding this
rectangle. The sphere also holds a right parallelepiped that measures 28 by 28
by 33 fingers. The face 28 by 28 fingers represents a square cubit and
corresponds to the area of the long rectangle measuring 16 by 49 fingers.
16x16
+ 49x49 = 28x28 + 28x28 + 35x35
(diameter squared)
RMP 10
'4 '28 times 1 '2 '4 equals '2 (see RMP 7)
A rectangle measures 8 by 49 fingers. The sphere around this
rectangle holds a right parallelepiped that measures 1 royal cubit x 10 palms x
9 fingers = 28 by 40 by 9 fingers. The narrow faces measure 9 by 40 fingers
each; their diagonals measure exactly 41 fingers, according to the triple
9-40-41.
8x8 + 49x49 = 9x9 + 28x28 + 40x40 9x9 + 40x40 = 41x41
Imagine a sphere holding the rectangle 9 by 40 fingers and calculate
its surface using the series 3 '9 '33 and 3 '8 '60:
9x9 plus 40x40 =
41x41 = 1681
1681 x 3 '9 '33 --
5043 187 51
= 5281
1681 x 3 '8 '60 --
5043 210 28
= 5281
A new value for the number re: '1681 of 5281
311
(plus 355) 666 1021
... 4926 (2463) 5281
5636
99
(plus 113) 212 325
... 1568 (784)
1681 1794
RMP 11 '7 times 1 '2 '4 equals '4
A rectangle measures 4 by 49 fingers. The imaginary sphere around
this rectangle holds a right parallelepiped that measures 14 by 14 by 45
fingers. Volume or capacity 12 '28 '56 hekat. Using the value '20 of 63 for re,
this volume can be transformed into a cylinder whose diameter, circumference
and height measure 5 palms, 63 fingers and 1 royal cubit.
RMP 12
'14 times 1 '2 '4 equals '8
A rectangle measures 2 by 49 fingers. The sphere around it holds a
right parallelepiped that measures 20 by 22 by 39 fingers. The numbers 22 and
39 provide a good value for the square root of 3 '7 or '7 of 22.
39 x 39 x 7
plus 1 = 22 x 22 x 22
RMP 13
'16 '112 times 1 '2 '4 equals '8
A rectangle composed of six rectangles measures 2 by 49 fingers
(see RMP 12). The smallest rectangle measures '112 by '4 royal cubit and has an
area of 1 '2 '4 square fingers. The largest rectangle measures '16 by 1 royal
cubit and has an area of 49 square
fingers (RMP 14).
RMP 14
'28 times 1 '2 '4 equals '16
A rectangle measures 1 by 49 fingers. A square that measures 7 by
7 fingers has the same area. Imagine a sphere around the square and calculate
its surface. Using the value 3 '7 for re you will obtain 308 square fingers.
7x7 plus 7x7
times 3 '7 equals
308
RMP 15
'32 '224 times 1 "3 '3 equals '14
A rectangle measures 1 by 56 fingers. The rectangles 4 by 14
fingers and 8 by 7 fingers have the same area. Draw a circle around the
rectangle 4 by 14 fingers and imagine a hemisphere standing on the circle. Its
surface measures practically 333 square fingers. Now imagine a sphere holding
the rectangle 8 by 7 fingers. The surface measures practically 355 square
fingers.
RMP 16
'2 times 1 "3 '3 equals 1
A rectangle measures 14 by 56 fingers and has the same area as a
square that measures 7 by 7 palms or 28 by 28 fingers. Imagine a sphere around
the square and calculate its surface. Using the value 3 '7 for re, the surface
measures 308 square palms. Using the value '784 of 2463 for re, the surface
measures 2463 square fingers.
RMP 17
'3 times 1 "3 '3 equals "3
A triple square, a double square and a square measure '6 by 1
square cubit, '6 by "3 square cubit, and '6 by '3 square cubit. The
diagonals of the square, of the double square and of the triple square can be
approximated by means of my number columns that begin with the lines 1-1-2 and
1-1-5. Draw a circle around each figure. Their areas will maintain the ratio
2:5:10.
RMP 18
'6 times 1 "3 '3 equals '3
The area of a rectangle measures '3 square cubit. Transform this
area into a square. Imagine a sphere holding the square. Calculate its surface
using the value '784 of 2463 for re. The diameter squared measures '3 plus '3 =
"3 square cubits. Multiply this area by 2463 and you obtain 1642 square
fingers.
RMP 19
'12 times 1 "3 '3 equals '6
The area of a rectangle measures '6 square cubit. Transform this
area into a square. Imagine a sphere holding the square. Calculate the surface
of the sphere:
'6 '6 square cubits x
2463 = 821 square fingers
A highly demanding task, solvable in a very simple manner (mistake
only one square millimeter).
RMP 20
'24 times 1 "3 '3 equals '12
The area of a rectangle measures '12 square cubit. Transform it into a square. Imagine a sphere holding
the square. Transform the surface of the sphere into a circle. Imagine a second
sphere holding the circle. It will be the sphere from RMP 18, whose surface
measures practically 1642 square fingers.
Rhind 1 / Rhind 2 / Rhind 3 / Rhind 4 / Rhind 5 / Rhind 6 / Rhind 7 / Rhind 8